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0=6x^2-12x+6
We move all terms to the left:
0-(6x^2-12x+6)=0
We add all the numbers together, and all the variables
-(6x^2-12x+6)=0
We get rid of parentheses
-6x^2+12x-6=0
a = -6; b = 12; c = -6;
Δ = b2-4ac
Δ = 122-4·(-6)·(-6)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-12}{-12}=1$
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